6- A particle is projected from ground at angle 45- with initial veloci20- m-s- Find -a- change in velocity -b- magnitude of average velocity in a time interval from t-0 to t-3s-

You visited us 5 times! Enjoying our articles? Unlock Full Access!

Distance and Displacement

6. A particle...

Question

6. A particle is projected from ground at angle 45^° with initial veloci20\sqrt{} m/s. Find (a) change in velocity (b) magnitude of average velocity in a time interval from t=0 to t=3s.

Open in App

Solution

Suggest Corrections

Similar questions

45^{\circ}

20 \sqrt{2} m / s .

t = 0

t = 3 s

20 m / s

30^{\circ}

t = 0

t = 0.5 s

(g = 10 m / s^{2})

20

30^{o}

t = 0

t = 0.5

(g = 10 m / s^{2})

30^{0}

m / s^{2}

20 m / s

30^{\circ}

t = 0

t = 0.5 s

(g = 10 m / s^{2})

Join BYJU'S Learning Program