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Le Chatelier's Principle for Del N Equals to 0

6. At 817^° C...

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6. At 817^° C Ko for the reaction b/w CO2 and excess of hot graphite is 10 atm. a) What are the equilibrium concentration of the gases at 817^° C and 5 atm total pressure? b) At what total pressure does the gas contains 5% CO2 by volume?

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817^{o} C

K_{p}

for the reaction between

{C O}_{2} (g)

and excess hot graphite (s) is

10 a t m

.
(a) What are the equilibrium concentrations of gases at

817^{o} C

and a total pressure of

5 a t m

?
(b) At what total pressure the gas contains

5

{C O}_{2}

817^{o} C

K_{p}

for the reaction between

{C O}_{2} (g)

and excess of hot graphite (s) is

10 a t m

.
(a) What are the equilibrium pressures of the gases at

817^{o} C

and a total pressure of

5 a t m

?
(b) At what total pressure does the gas contain

5

{C O}_{2}

817

K_{p}

for the reaction between

C O_{2} (g)

and excess hot graphite

(s)

(a) The sum of equilibrium concentration of the gases at

817^{o} C

is X M and a total pressure of 5 atm.
(b) At Y atm total pressure, the gas contains

5 %

C O_{2}

1000 (X + Y)

817^{o} C

K_{p}

for the reaction between

{C O}_{2}

and excess hot graphite to form

2 C O (g)

10

.
(i) What is the analysis (mole fraction) of the gases at equilibrium at

817^{o} C

and a total pressure of

4 a t m

? What is the partial pressure of

{C O}_{2}

at equilirbrium?
(ii) At what total pressure will the gas mixture have

6

{C O}_{2}

817^{0} C, K_{p}

for the reaction between pure

C O_{2}

and excess hot graphite to form

2 C O (g)

is 10 atm.
What is the analysis of the gases at equilibrium at

817^{0} C

& a total pressure of 4.0 atm? What is the partial pressure of

C O_{2}

at equilibrium?

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