Question

$6$ boys and $6$ girls sit in a row at random. The probability that all the girls sit together is?

• A. $\frac{1}{432}$
• B. $\frac{12}{431}$
• C. $\frac{1}{132}$
• D. None of these

Answer 1

The correct option is C $\frac{1}{132}$

Given 6 boys and 6 girls

∴∴ Number of ways in which 6 boys and 6 girls together sitting in a row =7!

6 girls sitting arrangement =6!

∴∴ Required probability =$\frac{7!\times 6!}{12!}$7!×6!12!

=1/132