You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trend in Ionisation Enthalpy

6C14 and 7N...

Question

$_{6} C^{14}$ and $_{7} N^{15}$ are the examples of.

Isotopes

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Isobars

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Isotones

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Mirror nuclei

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Isotones
Number of neutrons in carbon, $N_{C} = 14 - 6 = 8$
Number of neutrons in nitrogen, $N_{N} = 15 - 7 = 8$
As both have same number of neutrons, thus $_{6} C^{14}$ and $_{7} N^{15}$ are the example of isotones.

Suggest Corrections

Similar questions

_{7} N^{15}

_{8} O^{16}

_{6} C^{14}

_{7} N^{14}

If Avogadro's number is $6 \times 10^{23}$ , then the number of protons, neutrons and electrons in 14 g of $_{6} C^{14}$ are respectively:

\in

N

\frac{n^{5}}{5} + \frac{n^{3}}{3} + \frac{7 n}{15}

_{7} N^{15}

15.0011 a m u

_{8} O^{16}

15.99492 a m u

m_{P} = 1.00783 a m u

_{8} O^{16}

Join BYJU'S Learning Program