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6C14 and 7N...

Question

$_{6} C^{14}$ and $_{7} N^{15}$ are the examples of.

Isotopes

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Isobars

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Isotones

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Mirror nuclei

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Solution

The correct option is C Isotones
Number of neutrons in carbon, $N_{C} = 14 - 6 = 8$
Number of neutrons in nitrogen, $N_{N} = 15 - 7 = 8$
As both have same number of neutrons, thus $_{6} C^{14}$ and $_{7} N^{15}$ are the example of isotones.

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Similar questions

_{7} N^{15}

_{8} O^{16}

_{6} C^{14}

_{7} N^{14}

If Avogadro's number is $6 \times 10^{23}$ , then the number of protons, neutrons and electrons in 14 g of $_{6} C^{14}$ are respectively:

\in

N

\frac{n^{5}}{5} + \frac{n^{3}}{3} + \frac{7 n}{15}

_{7} N^{15}

15.0011 a m u

_{8} O^{16}

15.99492 a m u

m_{P} = 1.00783 a m u

_{8} O^{16}

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