$6!$ can be written as

\frac{5}{5!}

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\frac{5!}{5}

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\frac{7}{7!}

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\frac{7!}{7}

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Solution

The correct option is D $\frac{7!}{7}$
We know that
$7! = 7 \times 6!$
Divide both the sides by $7,$ we get
$\frac{7!}{7} = \frac{7 \times 6!}{7}$
$\frac{7!}{7} = 6!$

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