Question

$6$ cows can graze a field in $28$ days. How long would $14$ cows take to graze the same field?

Answer 1

Let x be the number of days. Then, we have:

$\begin{array}{ccc}\text{No. of days}& 28& x\\ \text{No. of cows}& 6& 14\end{array}$

Clearly, more cows will take fewer days to graze the field.

So, it is a case of inverse proportion.

Now, $28\times 6=x\times 14$

$\Rightarrow x=\frac{28\times 6}{14}$

$\Rightarrow x=12$

Therefore, $14$ cows will take $12$ days to graze the field.