Question

$6$ cows can graze a field in $28$ days. How long would $14$ cows take to graze the same filed?

Answer 1

If more number of cows, less number of days required to graze the field. Therefore it's inversely proportional.

Let us consider the required number of days to be $x$, then
$6\times 28=14\times x$

$x=(6\times 28)/14=12$

$\therefore 12$ days are required.