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Law of Conservation of Mechanical Energy

6. Each of th...

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6. Each of the two strings of length 51.6cm and 49.1cm are tensions separately by 20N force. Mass per unit length of both strings is same and equal to 1g/m .when both Strings vibrate simultaneously the number of beats is

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Q. Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 g/m. When both strings vibrate simultaneously the number of beats is

Q. A tuning of fork of frequency 392 Hz, resonates with 50 cm length of a string under tension (T). If length of the string is decreased by 2%, keeping the tension constant, the number of beats heard when the string and the tuning fork made to vibrate simultaneously is :-

Q. Two strings (fixed at both ends)

P

Q

of equal length, made of same material and vibrating in same mode produces beats of frequency

5 Hz

Q

is vibrating at a frequency

460 Hz

. If the tension in string

P

increases, the beat frequency increases to

7 Hz

. The initial frequency of vibration for string

P

Q. Two strings (fixed at both ends)

P

Q

of equal length, made of same material and vibrating in same mode produces beats of frequency

5 Hz

. Initial string

Q

is vibrating at a frequency

460 Hz

. If the tension in string

P

increases, the beat frequency increases to

7 Hz

. The initial frequency of vibration for string

P

Q. Two identical strings of the same material, same diameter and same length are in unison, when stretched by the same tension. If the tension on one string is increased by

21

%, the number of beats heard per second is

10

. The frequency of the note in hertz, when the strings are in unison is :

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