The correct option is D ₹3,600
Given,
Cost of 6 tickets is ₹2,160
We know that more the number of tickets, more will be the amount.
So, Number of tickets(x)∝Cost(y)
∴ x1y1 = x2y2
Given,
x1 = 6 tickets
y1 = ₹2,160
x2 = 6+4 = 10 tickets
and y2 = total amount for 10 tickets
⇒y2 = x2×y1x1
⇒y2 = 10×2,1606 = ₹3,600
Hence, the total collection is ₹3,600.