You visited us 1 times! Enjoying our articles? Unlock Full Access!

Uses of Slaked Lime

6) G (kJ/mol)...

Question

6) G (kJ/mol) values at 298 K for Ag+ (aq), Cl-(aq) and AgCI (s) are 77,-129 and -109 respectively for the given reaction, Ag (aq) + C (aq) AgCI(s) Then the solubility product of AgCl is

Open in App

Solution

Suggest Corrections

Similar questions

A g^{+} (a q) + C l^{-} (a q) ⇌ A g C l (s)

Δ G^{o}

A g^{+} (a q), C l^{-} (a q)

A g C l (s)

^{- 1}

K_{s p}

10^{10}

Δ G_{f}^{⊖}

A g^{\oplus} (a q) + C l^{⊖} (a q) \to A g C l (s)

Δ G^{⊖_{A g C l}} = - 109 k J m o l^{- 1}

Δ G_{(C l^{⊖})}^{⊖} = - 129 k J m o l^{- 1}

Δ G_{(A g^{\oplus)}}^{⊖} = - 77 k J m o l^{- 1}

A g_{(aq)}^{+} + C l_{(aq)}^{-} ⇌ A g C l_{(s)}

\begin{matrix} Species & Δ G_{f}^{\circ} (kJ/mol) A g_{(aq)}^{+} & + 77 C l_{(aq)}^{-} & - 129 A g C l_{(s)} & - 109 \end{matrix}

E_{cell}^{\circ}

298 K

A g C l

A g^{+} (a q) + C l^{-} (a q)_{\to} A g C l (s)

E^{o}

{log}_{10} K_{s p} (A g C l)

6.539 \times 10^{- 2} g

A g C l

{log}_{10} \frac{[Z n^{2 +}]}{[A g^{+}]^{2}}

A g^{+} + e^{-} \to

E^{o} = 0.80 V

Z n^{2 +} + 2 e^{-} \to

E^{o} = - 0.76 V

= 65.39

AgCl (s) + e^{-} \to Ag (s) + C l^{-} (aq)

E^{\circ} = 0 .22V

A g^{+} (a q) + e^{-} \to A g (s)

E^{\circ} = 0 .80V

A g C l

Join BYJU'S Learning Program