Question

6. How many grams of sodium chloride are there in 30.0 mL of a 1.2 M solution of sodium chloride?(MMPP)

Answer 1

Molar mass of NaCl (m) = 58.5 g
Volume of NaCl (V) = 30 mL
Molarity (M) = 1.2 M
$Molarity=\frac{Givenmass\times 1000}{Molarmass\times Volume}$
$$\begin{gathered} 1.2=\frac{Givenmass\times 1000}{58.5\times 30} \\ Givenmass=2.106g \end{gathered}$$