Question

$6$ moles of an ideal gas expand isothermally and reversibly from a volume of $1$ litre to a volume of $10$ litres at ${27}^{o}C$. What is the maximum work done?

• A. $47kJ$
• B. $100kJ$
• C. $0$
• D. $34.465kJ$

Answer 1

The correct option is D $34.465kJ$

For isothermal change,

$W=-2.303nRTlog\frac{V_2}{V_1}$

Givenn $n=6,T={27}^{o}C=273+27=300K$

$V_1=1L,V_2=10L$

$W=-2.303\times 6\times 8.314\times 300log\frac{10}{1}$

$=34.465kJ$

Hence, option D is correct