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Chord

6.OA and OB a...

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6.OA and OB are respectively perpendiculars to chords CD and EF of the circle whose centre is O. If OA=OB then prove arc CE congruent to arc DF.

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In figure, arc AB is congruent to arc AC and O is the centre of the circle. Prove that OA is the perpendicular bisector of BC. [4 MARKS]

Q. OA perpendicular to OD, OC perpendicular to OB, OD = OA, OC = OB. Then prove that AB = CD

Q. If OA and OB are equal perpendicular chords of the circles

x^{2} + y^{2} - 2 x + 4 y = 0

, then equation of OA and OB are where O is origin.

Q. In the given figure, CD and AB are intersecting chords and EF is a tangent to the circle. If OD = 4 cm, OB = 12 cm, OA = 4 cm and DE = 4 cm, then the length of EF is equal to

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is a point on a circle with centre

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