Question

$6\Omega ,8\Omega$ and $10\Omega$ resistance are connected in series. Find total resistance of the circuit.

Answer 1

The same current flows through each part of a series circuit. The total resistance of a series circuit is equal to the sum of individual resistances.

Hence,

$R_{eq}=R_1+R_2+R_{3}5$

$\Rightarrow R_{eq}=6+8+10$

$\Rightarrow R_{eq}=24\Omega$