6th term in expansion of 2x2 - 1-3x210 is

Applying T_r+1 = ^n C _rx^n rd for (x+a)^n Hence T_6 = ^10 C _5(2x^2)^5( 1/3x^2)^5 = (10!/5!5!)(32) (1/243) = 896/27 ...

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General Term of Binomial Expansion

6th term in e...

Question

$6^{t h}$ term in expansion of $(2 x^{2} - \frac{1}{3 x^{2}})^{10}$ is

$\frac{4580}{17}$

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- $\frac{896}{27}$

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$\frac{5580}{17}$

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None of these

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6^{th}

{(2 x^{2} - \frac{1}{3 x^{2}})}^{10}

6^{th}

{(2 x^{2} - \frac{1}{3 x^{2}})}^{10}

6^{t h}

{(2 x^{2} - \frac{1}{3 x^{2}})}^{10}

$6^{t h}$ term in expansion of $(2 x^{2} - \frac{1}{3 x^{2}})^{10}$ is

{(\frac{3 x^{2}}{5} + \frac{5}{3 x^{2}})}^{10}

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