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Question

6th term in expansion of (2x2−13x2)10 is


A

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B

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C

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D

None of these

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Solution

The correct option is B


Applying Tr+1 = nCrxn−rd for (x+a)n

Hence T6 = 10C5(2x2)5(- 13x2)5

= - 10!5!5!32 × 1243 = - 89627


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