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Question

6×103mol K2Cr2O7 reacts completely with 9×103 mol of Xn+ to give XO3 and Cr+3 The valve of n is:


A

1

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B

2

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C

3

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D

5

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Solution

The correct option is A

1


K2Cr2O7 +Xn+ XO3Cr+3

Oxidation state of Chromium inK2Cr2O7=+6.Oxidation state of X inXO3=+5Change in oxidation state of X=(5n)

6×6×103 = (5-n)×9×103

4= 5-n

N =1


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