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Question

(6 × 5 + 30) ÷ (10 + 50)-100 ÷ 2


A

-94

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B

-49

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C

49

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D

98

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Solution

The correct option is B

-49


As we know, order of operation of BODMAS is as follows

Brackets

Of

Division

Multiplication

Addition

Subtraction

(6 × 5 + 30) ÷ (10 + 50)-100 ÷ 2

= (30 +30) ÷ 60 - 100 ÷ 2

= (30 +30) ÷ 60 - 50

= 1 – 50

= -49


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