Question

60 cc of a liquid of relative density 1.4 is mixed with 40 cc of another liquid of relative density 0.8. The density of the resulting mixture will be

• A. $1.16$ g/cc
• B. $2.26$ g/cc
• C. $11.6$ g/cc
• D. $116$ g/cc

Answer 1

The correct option is A $1.16$ g/cc

Given:

Volume 1$=V_1=60cc$

Volume 2$=V_2=40cc$

Relative Density of liquid 1$=d_1=1.4$

Relative Density of liquid 2$=d_2=0.8$

As $density=\frac{mass}{volume}$

$mass=density\times volume$

$\text{mass of liquid 1}=m_1=1.4\times 60=84cc$

$\text{mass of liquid 2}=m_2=0.8\times 40=32cc$

$\text{Resultant density}\left(d_{net}\right)=\frac{\text{Resultant mass}}{\text{Resultant Volume}}$

$\text{Resultant mass}=m_1+m_2=84cc+32cc=116cc$

$\text{Resultant volume}=V_1+V_2=60cc+40cc=104cc$

$d_{net}=\frac{116}{104}=1.16$

Net relative density is $1.16$ hence the density is $1.16g/cc$