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Empirical & Molecular Formula

60 mL of a mi...

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60 mL of a mixture of equal volume of $C l_{2}$ and an oxide of chlorine was heated and then cooled back to the original temperature. The resulting gas mixture was found to have a volume of 75 mL. On treatment with caustic soda solution, the volume contracted to 15 mL. Assume that all measurements are made at the same T and P. Deduce the simplest formula for oxide of $C l_{2}$ and calculate its molar mass. The oxide of $C l_{2}$ on heating decomposes quantitatively to $O_{2}$ and $C l_{2}$ . If the molar mass is $x$ gm/mol, then find the nearest integral value of $x$ .

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Solution

The given change is
$- Before reaction (in mL) After reaction(in mL) C l_{2} + 300 C l_{2} O_{n} 300 Δ - \to 2 C l_{2} 3060 (n / 2) O_{2} 0 15 n$
On passing the gaseous mixture through KOH, $C l_{2}$ is absorbed and $O_{2}$ is given out.
Volume of $O_{2} l e f t = 15$
By the change, $15 n = 15$
$n = 1$
Oxide of chlorine is $C l_{2} O$
so molar mass of $C l_{2} O = 71 + 16 = 87 g m / m o l e$

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