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Temperature-Volume Relationship

600.0 mL of...

Question

600.0 $m L$ of air is at 20 $^{0} C$ . What is the volume at 60 $^{0} C$ ?

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Solution

$V_{1} / T_{1} = V_{2} / T_{2}$
(600.0 $m L$ ) / (293.0 $K$ ) = ( $x$ ) / (333.0 $K$ ); $x$ = 682 $m L$

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