(600+9)^2=(600)^2+26009+(9)^2

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Solution

Yes you are going correctly
(600+9)^2=(600)^2+26009+(9)^2
=360000+10800+81
=370881

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Similar questions

$\frac{1 + s i n 600^{\circ} - c o s 600^{\circ}}{1 + s i n 600^{\circ} + c o s 600^{\circ}}$ = ?

\frac{{tan}^{2} 60^{0} + 4 {sin}^{2} 45^{0} + 3 {sec}^{2} 30^{0} + 5 {cos}^{2} 90^{0}}{csc 30^{0} + sec 60^{0} - {cot}^{2} 30^{0}} =

(i) 600 \times 4

(i i) 4 \times 500

(i i i) 9 \times 900

(v i) 500 \times 6

(v) 200 \times 9

\sqrt{2 + \sqrt{2 + 2 cos (π + 60^{0})}}

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