Question

600 person took dip in a rectangular tank which is 60 meter long and 40 meter broad.What is the rise in the level of water in the tank, if the average displacement of water by a person is 0.04 $m^3$ ?

Answer 1

Average displacement of water by one person $=0.04m^3$

Thus, displacement of water by 600 person $=0.04m^3\times 600=24m^3$

Area of base of rectangular tank $=60m\times 40m=2400m^2$

Thus, rise in water level = Volume of water displaced $÷$ Area of base of rectangular tank

$=\frac{24m^3}{2400m^2}=0.01m=1cm$