Question

62. 58. Balance the following equation. Also, name the products formed.

${\mathrm{CO}}_2+\mathrm{C}\to \mathrm{CO}$

Answer 1

Step 1:- List the number of atoms of different element present in the unbalanced equation

The given chemical equation is as follows:

${\mathrm{CO}}_2+\mathrm{C}\to \mathrm{CO}$

Element	Number of atoms in reactants	Number of atoms in products
C	2	1
O	2	1

Step 2:- Start balancing with the compound that contains maximum number of atoms (reactant or product)

• In this,(Carbon dioxide) CO₂ has a maximum number of atoms, check which element has the maximum number of atoms.
• Here Oxygen (O₂) has the maximum number of atoms.
• Balancing the Oxygen atom

Atoms of oxygen	In reactant	In product
Initial	(2 in CO2)	1 ( in CO)
Final (Balanced)	(2 in CO2) = 2 oxygen atoms	2 x (1 in CO) = 2 oxygen atoms

Now oxygen is balanced.

Step 3:- Balance the other atoms present in the equation

• Carbon is automatically balanced
• To equalize the number of atoms we can only add coefficients e.g. “2CO₂” instead of “C₂O₂” on the Product side”.

.The balanced molecular equation can be written as:

$\underset{\mathbf{Carbon}\mathbf{}\mathbf{dioxide}}{{\mathbf{CO}}_{\mathbf{2}}}\mathbf{+}\mathbf{}\underset{\mathbf{Carbon}}{\mathbf{C}}\mathbf{\to }\underset{\mathbf{Carbon}\mathbf{}\mathbf{monoxide}}{\mathbf{2}\mathbf{CO}}$