(625)^0.16 × (625)^0.09 =?
(a) 5
(b) 25
(c) 125
(d) 625.25

Open in App

Solution

(a) 5

We have:
${(625)}^{0.16} \times {(625)}^{0.09} = {(625)}^{0.16 + 0.09} = {(625)}^{0.25} = {(625)}^{\frac{25}{100}} = {(625)}^{\frac{1}{4}} = {\{(5)^{4}\}}^{\frac{1}{4}} = 5$

Suggest Corrections

Similar questions

Q. The value of

{(625)}^{0.16} \times (625)^{0.09}

A cube has a side of length 0.05 m. Find its volume in cubic cm.

$∣ ∣ ∣ ∣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ∣ ∣ ∣ ∣ = 5, t h e n t h e v a l u e o f ∣ ∣ ∣ ∣ \begin{matrix} b_{2} c_{3} - b_{3} c_{2} & a_{3} c_{2} - a_{2} c_{3} & a_{2} b_{3} - a_{3} b_{2} b_{3} c_{1} - b_{1} c_{3} & a_{1} c_{3} - a_{3} c_{1} & a_{3} b_{1} - a_{1} b_{3} b_{1} c_{2} - b_{2} c_{1} & a_{2} c_{1} - a_{1} c_{2} & a_{1} b_{2} - a_{2} b_{1} \end{matrix} ∣ ∣ ∣ ∣ i s$

\int_{0}^{\infty} \frac{d x}{(x + \sqrt{x^{2} + 1})^{5}} =

5 x y + 25 y + 3 x + 15

is factorised as

Join BYJU'S Learning Program

(625)0.16 × (625)0.09 =? (a) 5 (b) 25 (c) 125 (d) 625.25

(a) 5 We have: 6250.16×6250.09=6250.16+0.09=6250.25=62525100=62514=(5)414=5

(625)^0.16 × (625)^0.09 =?
(a) 5
(b) 25
(c) 125
(d) 625.25

(a) 5

We have:
${(625)}^{0.16} \times {(625)}^{0.09} = {(625)}^{0.16 + 0.09} = {(625)}^{0.25} = {(625)}^{\frac{25}{100}} = {(625)}^{\frac{1}{4}} = {\{(5)^{4}\}}^{\frac{1}{4}} = 5$