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Byju's Answer
Standard VIII
Mathematics
Exponent of a Product
6251/3× 16001...
Question
625
1
3
×
1600
1
3
= ___
A
50
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B
75
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C
100
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D
125
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Solution
The correct option is
C
100
625
1
3
×
1600
1
3
=
(
625
×
1600
)
1
3
(
∵
a
m
×
b
m
=
(
a
b
)
m
)
=
{
(
25
)
2
×
(
4
3
×
5
2
)
}
1
3
=
{
(
5
2
)
2
×
4
3
×
5
2
}
1
3
=
{
5
4
×
4
3
×
5
2
}
1
3
(
∵
(
a
m
)
n
=
a
m
n
)
=
{
5
4
+
2
×
4
3
}
1
3
(
∵
a
m
×
a
n
=
a
m
+
n
)
=
(
5
6
×
4
3
)
1
3
=
(
5
6
)
1
3
×
(
4
3
)
1
3
(
∵
(
a
×
b
)
m
=
a
m
×
b
m
)
=
5
6
×
1
3
×
4
3
×
1
3
(
∵
(
a
m
)
n
=
a
m
n
)
=
5
2
×
4
=
25
×
4
=
100
Suggest Corrections
0
Similar questions
Q.
(
64
125
)
−
2
/
3
÷
1
(
256
/
625
)
1
/
4
+
(
(
√
25
)
3
√
64
)
0
=
Q.
Evaluate:
(
64
125
)
−
2
3
÷
1
(
256
625
)
1
4
+
(
(
√
25
)
3
√
64
)
Q.
Solve :
(
64
125
)
−
2
/
3
+
1
(
256
625
)
1
/
4
+
(
√
25
3
√
64
)
0
=
61
16
Q.
Simplify:
(i)
(
27
)
4
3
+
(
32
)
0.8
+
(
0.8
)
−
1
(ii)
(
64
125
)
−
2
3
÷
1
(
256
625
)
1
4
×
√
25
3
√
64
(iii)
⎡
⎢ ⎢
⎣
5
⎛
⎜
⎝
8
1
3
+
27
1
3
⎞
⎟
⎠
3
⎤
⎥ ⎥
⎦
1
4
Q.
Find:
625
1
4
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