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Second Law of Motion

63. an object...

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63. an object is projected from ground with speed u at angle theta with horizontal the radius of curvature of its trajectory at maximum height from the ground is

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Q. An object is projected with speed

50 m/s

53^{\circ}

with horizontal from ground. The radius of curvature of its trajectory at

t = 1 sec

after projection will be:

(

g = 10 {m/s}^{2})

Q. A particle is projected from ground with initial speed

u

and projection angle

θ

from horizontal. Find the radius of curvature of trajectory of particle when during flight particle's velocity makes an angle

\frac{θ}{2}

with horizontal.

Q. A particle is projected with speed

u

θ

with the horizontal. Find the radius of curvature at the highest point of its trajectory.

Q. A projectile is projected at an angle of

45^{o}

with speed u. The radius of curvature of its trajectory at the maximum height is

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