Question

$(64{)}^2$ would have digit ____ at units place.

• A. 7
• B. 6
• C. 9
• D. 1

Answer 1

The correct option is B 6

In $(64{)}^2$, the digit in unit's place is the last digit at the multiplication of

$4\times 4=1\underset{–}{6}$

So, $6$ at units place

Therefore, B is the correct answer.