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Byju's Answer
Standard IX
Mathematics
Algebraic Identities
64a3 - 27b3 -...
Question
64
a
3
−
27
b
3
−
144
a
2
b
+
108
a
b
2
Open in App
Solution
64
a
3
−
27
b
3
−
144
a
2
b
+
102
a
b
2
(
4
a
)
3
−
(
3
b
)
3
−
4
a
×
4
a
×
3
×
3
b
+
(
4
a
)
(
3
b
)
2
(
3
)
(
4
a
−
3
b
)
3
Suggest Corrections
9
Similar questions
Q.
Solve:
64
a
3
−
27
b
3
−
144
a
2
b
+
108
a
b
2
.
Q.
Factorize
64
a
3
−
27
b
3
−
144
a
2
b
+
108
a
b
2
Q.
Factorise
64
a
3
-
27
b
3
-
144
a
2
b
+
108
a
b
2
Q.
Factorise each of the following: 64
a
3
– 27
b
3
– 144
a
2
b + 108a
b
2
Q.
State True or False.
64
a
3
−
27
b
3
−
144
a
2
b
+
108
a
b
2
=
(
4
a
−
3
b
)
(
4
a
−
3
b
)
(
4
a
−
3
b
)
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