64-23- 14-3 equals to-

64=4^3 As per question, (64)^ 23× (14)^ 3 After substituting the value of 64, (4^3)^ 23× (14)^ 3 On solving, we get the value as 4. ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation by Regrouping Terms

64-23× 14-3 e...

Question

$(64)^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}$ equals to:

4

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1

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16

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\frac{1}{4}

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Solution

The correct option is A $4$
$64 = 4^{3}$
As per question,
$(64)^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}$
After substituting the value of $64$ ,
$(4^{3})^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}$
On solving, we get the value as $4$ .

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Similar questions

{(64)}^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}

equals

Q. Evaluate:

(i) 2 \times 27^{\frac{1}{3}} \times 216^{- \frac{2}{3}}

(i i) 64^{- \frac{1}{3}} (64^{\frac{1}{3}} - 64^{- \frac{2}{3}})

[4 MARKS]

(64)^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}

Evaluate: ${(\begin{matrix} \frac{64}{125} \end{matrix})}^{\frac{- 2}{3}} \div \frac{1}{(\frac{256}{625})^{\frac{1}{4}}} + (\begin{matrix} \frac{(\sqrt{25})}{\sqrt[3]{64}} \end{matrix})$

In ch .1

A question

to simplify

64^1/3(64^1/3 - 64^2/3)

in this the solution is given as

= (4^3)^ -1/3[ ( 4^3)^1/3 - (4^3)^2/3 ]

how -1/3 came ?

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(64)−23×(14)−3 equals to:

The correct option is A 464=43 As per question, (64)−23×(14)−3 After substituting the value of 64, (43)−23×(14)−3 On solving, we get the value as 4.

$(64)^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}$ equals to:

The correct option is A $4$
$64 = 4^{3}$
As per question,
$(64)^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}$
After substituting the value of $64$ ,
$(4^{3})^{\frac{- 2}{3}} \times {(\frac{1}{4})}^{- 3}$
On solving, we get the value as $4$ .