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Concentration Terms

64 g of sulph...

Question

64 g of sulphur dioxide occupies 22.4 L volume at STP.
If true then enter 1, if false enter 0.

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Solution

64 gm of sulphur dioxide is equal to 1 mole, therefore 64 gm of $S O_{2}$ occupies 22.4 L at STP.

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