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Gay Lussac's Law, Avagadro's Law

64 g of sulph...

Question

64 g of sulphur dioxide occupies $22.4 L$ volume at STP.

A

True

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B

False

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Solution

The correct option is A True
Molecular mass of $S O_{2}$ is 64.
So, 1 mole (64 grams) of sulphur dioxide will occupy $22.4 L$ at STP. ( Avogadro's law)

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Q. 64 g of sulphur dioxide occupies 22.4 L volume at STP.

If true then enter 1, if false enter 0.

Q. (a) What is the volume occupied by the following gases at STP?
(i) 48 g of oxygen.
(ii) 16 g of sulphur dioxide
(b) Determine the molecular mass of a gas if 5 g of it occupies a volume of 4 litres at STP.

Q. Assertion :22.4 litres of sulphur dioxide at STP weighs 64 grams. Reason: 1 mole of sulphur dioxide is 64 grams.

One gram mole of a gas at STP occupies 22.4L volume. This fact was derived from –

Q. Amount of gas which occupies

22.4 L

volume at STP is equal to vapor density of the gas.

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Gay Lussac's Law, Avagadro's Law

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