Question

$64gm$ of organic compound contains $24gmC,8gmH$ and the rest oxygen. What is the empirical formula of the compound.

• A. $C{H}_{2}O$
• B. $C{H}_{4}O$
• C. $C_2{H}_{4}O$
• D. $C_2{H}_8{O}_2$

Answer 1

Answer: (B)

$C{H}_{4}O$

Elements mass	No. of moles	Simple ratio
$C=24g$	$\frac{24}{12}=2$	$\frac{2}{2}=1$
$H=8g$	$\frac{8}{1}=8$	$\frac{8}{2}=4$
$O=32g$	$\frac{32}{16}=2$	$\frac{2}{2}=1$

Empirical formula $=C{H}_{4}O$