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Solving Equations Algebraically

64 gold coins...

Question

64 gold coins are divided among two people A and B. If A is having 5 less than 2 times the number of coins B has, then the number of coins A has is .

A

23

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B

41

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C

32

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D

14

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Solution

The correct option is B 41
Given that the total number of coins
= 64
The number of coins B has = x
So, the number of coins A has
= 2x - 5

Thus,
2x-5 + x = 64
3x = 69
x = 23

The number of coins B has = 23.
The number of coins A has
= 2x - 5
= 46 -5
= 41.

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