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Standard XII

Chemistry

Factors Affecting Rate of Reaction

646 g of ammo...

Question

646g of ammonia is allowed to react with 1.144kg of CO2 to form urea identify the limiting reagent calculate the amount of urea formed and interacted quality of excess agent

2NH3+CO2----------- NH2CONH2+H2O

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Solution

The balanced equation is
2 NH3 + CO2
↓
H2NCONH2 + H2O

1. The entire quantity of ammonia
is consumed in the reaction. So
ammonia is the limiting reagent. Some
quantity of CO2 remains unreacted,
so CO2 is the excess reagent.
2) Quantity of urea formed
= number of moles of urea formed
× molar mass of urea
= 19 moles × 60 g mol–1
= 1140 g = 1.14 kg
Excess reagent leftover at the end of
the reaction is carbon dioxide.
Amount of carbon dioxide leftover
= number of moles of CO2 left
over × molar mass of CO2
= 7 moles × 44 g mol–1
= 308 g.
Reactants Products

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646g of ammonia is allowed to react with 1.144kg of CO2 to form urea identify the limiting reagent calculate the amount of urea formed and interacted quality of excess agent 2NH3+CO2----------- NH2CONH2+H2O

646g of ammonia is allowed to react with 1.144kg of CO2 to form urea identify the limiting reagent calculate the amount of urea formed and interacted quality of excess agent

2NH3+CO2----------- NH2CONH2+H2O