65 $\div$ 13 = 5 implies 13 can be subtracted 5 times from 65 till it reaches 0.

True

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False

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Solution

The correct option is A True

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Similar questions

{sin}^{- 1} \frac{3}{5} + {cos}^{- 1} \frac{12}{13} = {cos}^{- 1} \frac{33}{65}

{cos}^{- 1} \frac{12}{13} + {sin}^{- 1} \frac{3}{5} = {sin}^{- 1} \frac{56}{65}

\frac{3}{4} from \frac{1}{3}

\frac{- 5}{6} from \frac{1}{3}

\frac{- 8}{9} from \frac{- 3}{5}

\frac{- 9}{7} from - 1

\frac{- 18}{11} from 1

\frac{- 13}{9} from 0

\frac{- 32}{13} from \frac{- 6}{5}

- 7 from \frac{- 4}{7}

\frac{5}{9} from \frac{- 2}{3}

5 from \frac{- 3}{5}

{s i n}^{- 1} (\frac{3}{5}) + {c o s}^{- 1} (\frac{12}{13}) = {s i n}^{- 1} (\frac{56}{65})

{s i n}^{- 1} \frac{3}{5} - {c o s}^{- 1} \frac{12}{13} = {s i n}^{- 1} \frac{16}{65}

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