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Byju's Answer
Standard XII
Mathematics
Sequence
655, 439, 314...
Question
655, 439, 314, 250, 223 ?
A
215
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B
210
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C
195
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D
190
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E
none of these
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Solution
The correct option is
A
215
Solution
→
Given terms are 655,439,314,250,223,?
As
a
1
=
655
a
2
=
439
a
3
=
314
a
4
=
250
a
5
=
223
a
6
=
?
So,
a
1
−
a
2
=
655
−
439
=
216
=
6
3
a
3
−
a
2
=
439
−
314
=
125
=
5
3
a
3
−
a
4
=
−
250
+
314
=
64
=
4
3
a
4
−
a
5
=
−
223
+
250
=
27
=
3
3
So, we can observe difference b/w terms are cubes
of 6,5,4,3 so, is similar way
a
5
−
a
6
=
2
3
223
−
a
6
=
8
a
6
=
215
So, we find next term is 215
Suggest Corrections
0
Similar questions
Q.
655 439 314 250 223 (?)
Q.
If
5
p
2
−
7
p
−
3
=
0
and
5
q
2
−
7
q
−
3
=
0
,
p
≠
q
, then the equation whose roots are
5
p
−
4
q
and
5
q
−
4
p
is :
Q.
439
:
39
:
:
298
:
?
Q.
Roman number representation of
655
is
Q.
sec
2
θ
-
cot
2
(
90
°
-
θ
)
cosec
2
67
°
-
tan
2
23
°
+
(
sin
2
40
°
+
sin
2
50
°
)
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