$66 \div \frac{1}{3} = \frac{66}{1} \times \frac{3}{1}$

True

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False

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Solution

The correct option is A True

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Similar questions

Find $\frac{1^{3}}{1} + \frac{1^{3} + 2^{3}}{1 + 3} + \frac{1^{3} + 2^{3} + 3^{3}}{1 + 3 + 5} + . . .16$ terms.

\frac{1^{3}}{1} + \frac{1^{3} + 2^{3}}{1 + 3} + \frac{1^{3} + 2^{3} + 3^{3}}{1 + 3 + 5} + \dots . n

=

\frac{\sqrt{3} + \frac{1}{\sqrt{3}}}{1 - \sqrt{3}} - \frac{\sqrt{3} - \frac{1}{\sqrt{3}}}{1 + \sqrt{3}} = 1

$\frac{1^{3}}{1} + \frac{1^{3} + 2^{3}}{1 + 3} + \frac{1^{3} + 2^{3} + 3^{3}}{1 + 3 + 5} + . . . .$ to 16 terms =

Simplify $(\frac{1 + \sqrt{3}}{1 - \sqrt{3}}) + (\frac{1 - \sqrt{3}}{1 + \sqrt{3}})$

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