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Field Lines in Different Scenarios

66. The magni...

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66. The magnitude of the average electric field normally present in the atmosphere just above the surface of the earth is about 150 N/C ,directed inward towards the centre of the earth .This gives the total net surface charge carried by the earth to be ??

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Q. The magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about

150 N / C

, directed inward towards the center of the Earth. This gives the total net surface charge carried by the Earth to be : [Given

ϵ_{0} = 8.85 \times 10^{- 12} C^{2} / N - m^{2}, R_{E} = 6.4 \times 10^{6} m]

Q. The earth has a net electric charge that causes a field at points near its surface. The charge on the earth is supposed to be a result of an atmospheric battery created between ionosphere and the earth. The electric field near the earth's surface is believed to be

150 N C^{- 1}

and directed towards the centre of the earth. A man suggested that this electric field may be used in flying. What magnitude and sign of charge would a

60 k g

human have to acquire to overcome his or her weight?

Q. If atmospheric electric field is approximately

150 V/m

and radius of the earth is

6400 km

, then total charge on the earth's surface is

If the electric field intensity in a fair weather atmosphere is 100V/m, then the total charge on the earth surface is

Q. The earths surface has a negative surface charge density of

10^{- 9} C m^{- 2}

. The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralise the earths surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth =

6.37 \times 10^{6}

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