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Question

68.A body is projected horizontally from a height of 78.4m with a velocity of 10m/s Its velocity after 3seconds is (g=10m/s2)(Take direction of projection as I and vertically upward direction as j)

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Solution

Velocity after 3 seconds:v=u+at =u+gt =10i^+10-j3 =10i^-30j m/s

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