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Byju's Answer
Standard XII
Chemistry
Catalysis
69.Heat of ne...
Question
69.Heat of neutralisation of oxalic acid is -53.35 KJ/g.eq using NaOH. Calculate the volume of delta(H) for the given reaction H2C2O4=====>C2O4 +2H
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Similar questions
Q.
Heat of neutralisation of oxalic acid is
−
106.7
k
J
m
o
l
−
1
using
N
a
O
H
hence
△
H
of
H
2
C
2
O
4
→
C
2
O
2
−
4
+
2
H
+
is
Q.
The heat of neutralisation of oxalic acid is
−
25.4
K
c
a
l
m
o
l
−
1
using strong base,
N
a
O
H
. Hence, the enthalpy change of the process is
H
2
C
2
O
4
→
←
2
H
⊕
+
C
2
O
2
−
4
iS
Q.
Oxalic acid,
H
2
C
2
O
4
forms two series of salt,
H
C
2
O
4
−
and
C
2
O
4
−
. If
0.9
g of oxalic acid is in
100
mL solution,
H
C
2
O
4
−
and
C
2
O
4
−
have normality respectively
:
Q.
Enthalpy of neutralisation of acetic acid by
N
a
O
H
is
−
50.6
k
J
m
o
l
−
1
. Calculate
Δ
H
for ionisation of
C
H
3
C
O
O
H
. Given, the heat of neutralisation of a strong acid with a strong base is
−
55.9
k
J
m
o
l
−
1
.
Q.
1.575
g
of oxalic acid
(
H
2
C
2
O
4
.
x
H
2
O
)
are dissolved in water and the volume made upto
250
m
l
. On titration,
16.68
m
l
of this solution requires
25
m
l
of
N
15
N
a
O
H
solution for complete neutralization. Calculate the value
x
.
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