69 The roots of the quadratic equation (A2+b2)x2-2(ac+bd)x+(C2+D2)=0 are equal.Prove that a/b=c/d.

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(a^{2} + b^{2}) x 2 - 2 (a c + b d) x + (c^{2} + d^{2}) = 0 a r e e q u a l, p r o v e t h a t \frac{a}{b} = \frac{c}{d}

(a^{2} + b^{2}) x^{2} + 2 (a c + b d) x + c^{2} + d^{2} = 0

(a^{2} + b^{2}) x^{2} - 2 (a c + b d) x + (c^{2} + d^{2}) = 0

\frac{a}{b} = \frac{c}{d}

(a^{2} + b^{2}) x^{2} - 2 (a c + b d) x + (c^{2} + d^{2}) = 0

\frac{a}{b} - \frac{c}{d} =

(a^{2} + b^{2}) x^{2} - 2 (a c + b d) x + (c^{2} + d^{2}) = 0

\frac{a}{b} = \frac{c}{d}

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