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Question

6a213a+6=?(a) (2a+3)(3a2)(b) (2a3)(3a+2)(c) (3a2)(2a3)(d) (3a+1)(2a3)


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    Solution

    6a213a+6=6a29a4a+6 6×6=36 36=(9)×(4)13=94=3a(2a3)2(2a3)=(2a3)(3a2)


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