Question

6gm. of urea is dissolved in 90 gm of water. The Relative lowering of vapour pressure is equal to ___

• A. 0.1
• B. 0.2
• C. 0.02
• D. 0.06

Answer 1

The correct option is C 0.02

$\frac{p^{\circ }-p}{p^{\circ }}=\frac{w}{m}\times \frac{M}{W}=\frac{6}{60}\times \frac{18}{90}=\frac{1}{50}=0.02$