6gm of urea is dissolved in 90gm of water. Relative lowering of vapour pressure is:

0.02

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0.2

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0.002

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0.04

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Solution

The correct option is D 0.02
Relative lowering of vapour pressure, $\frac{Δ P}{P} = \frac{\frac{W_{2}}{M_{2}}}{\frac{W_{1}}{M_{1}}}$
Relative lowering of vapour pressure, $\frac{Δ P}{P} = \frac{\frac{6 g}{60 g/mol}}{\frac{90 g}{18 g/mol}}$
Relative lowering of vapour pressure $\frac{Δ P}{P} = \frac{0.1}{5}$
Relative lowering of vapour pressure $= 0.02$

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6gm of urea is dissolved in 90gm of water. Relative lowering of vapour pressure is:

The correct option is D 0.02Relative lowering of vapour pressure, ΔPP=W2M2W1M1Relative lowering of vapour pressure, ΔPP= 6 g 60 g/mol 90 g 18 g/mol Relative lowering of vapour pressure ΔPP=0.15Relative lowering of vapour pressure =0.02