$6 x^{2} + 5 x - 4 = 0$ . find the values of X

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Solution

$6 x^{2} + 5 x - 4$
Factorising, we get
$\Rightarrow 6 x^{2} - 3 x + 8 x - 4 = 0$
$\Rightarrow 3 x (2 x - 1) + 4 (2 x - 1) = 0$
$\Rightarrow (3 x + 4) (2 x - 1) = 0$
$\Rightarrow 3 x + 4 = 0$
& $2 x - 1 = 0$
$3 x + 4 = 0 \Rightarrow x = \frac{- 4}{3}$
$2 x - 1 = 0 \Rightarrow x = \frac{1}{2}$

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