$(6 x^{5} - 4 x^{4} + 8 x^{3} + 2 x^{2}) \div 2 x^{2}$

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Solution

$\frac{6 x^{5} - 4 x^{4} + 8 x^{3} + 2 x^{2}}{2 x^{2}}$
$= 3 x^{3} - 2 x^{2} + 4 x + 1$

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Similar questions

Q. Divide :

(6 x^{5} - 4 x^{4} + 8 x^{3} + 2 x^{3}) \div 2 x^{2}

Q. Divides and write the quotient and the remainder.

({6 x}^{5} - {4 x}^{4} + {8 x}^{3} + {2 x}^{2}) \div {2 x}^{2}

Divide. Write the quotient and the remainder.
(a) $(21 x^{4} - 14 x^{2} + 7 x) \div 7 x^{3}$
(b) $(6 x^{5} - 4 x^{4} + 8 x^{3} + 2 x^{2}) \div 2 x^{2}$
(c) $(25 m^{4} - 15 m^{3} + 10 m + 8) \div 5 m^{3}$

Q. Finding the square root of the polynomial

4 x^{4} + 8 x^{3} + 8 x^{2} + 4 x + 1.

Q. How

[4 x^{4} + 8 x^{3} + 8 x^{2} + 4 x + 1]

can be simplified to

(2 x^{2} + 2 x + 1)^{2}

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(6x5−4x4+8x3+2x2)÷2x2

6x5−4x4+8x3+2x22x2=3x3−2x2+4x+1

$(6 x^{5} - 4 x^{4} + 8 x^{3} + 2 x^{2}) \div 2 x^{2}$

$\frac{6 x^{5} - 4 x^{4} + 8 x^{3} + 2 x^{2}}{2 x^{2}}$
$= 3 x^{3} - 2 x^{2} + 4 x + 1$