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First Fundamental Theorem of Calculus

6 x3+5 x2-21 ...

Question

6x³ + 5x² $-$ 21x + 10, 3x $-$ 2

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Solution

Here, quotient = 2x² + 3x $-$ 5
and remainder = 0

$∴ 6 x^{3} + 5 x^{2} - 21 x + 10 = (3 x - 2) (2 x^{2} + 3 x - 5) + 0$

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