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Question

6y2 + 17y + 12 = 0.

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Solution

The given quadratic equation is 6y2 + 17y + 12 = 0.
On splitting the middle term 17y as 9y + 8y, we get:
6y2 + 9y + 8y + 12 = 0
=> 3y(2y + 3) + 4(2y + 3) = 0
=> (2y + 3) (3y + 4) = 0
We know that if the product of two numbers is zero, then at least one of them must be zero.
Thus,
2y + 3 = 0 or 3y + 4 = 0
=> y = –32 or y = –43
Therefore, the solution of the given equation is y = –32 , –43.

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