The correct option is C 31In this series each subsequent term is #160;obtained by adding 6,8,10,14,......respectively in the previous term. Hence the #160;m ...

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Standard XII

Mathematics

Series

7 13 21 ? 43 ...

Question

7 13 21 ? 43 57

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Solution

The correct option is C 31
In this series each subsequent term is obtained by adding 6,8,10,14,......
respectively in the previous term. Hence the missing term is 21+10=31.

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Similar questions

Q. Which represents correct hexaploid nature of Wheat?

	Monosomic	Haploid	Nullisomic	Trisomic
(A)	$21$	$28$	$42$	$43$
(B)	$7$	$28$	$40$	$42$
(C)	$21$	$7$	$42$	$43$
(D)	$41$	$21$	$40$	$43$

Q. Fill in the blanks with

>, <

=

.
(i)

22 \times (- 36) + (- 42) \div (- 3) □ 9 \times 56 \times (- 8)

(ii)

26 - 22 + 21 \div (- 7) □ 43 - 11 - 13

(iii)

(- 16) \div [(- 13) + (- 3)] □ 12 \div [(- 3) - 0]

Question 180(iii)

Simplify

${(\frac{4}{13})}^{4} \times {(\frac{13}{7})}^{2} \times {(\frac{7}{4})}^{3}$

Q. Multiply

2 \frac{1}{3} \times 4 \frac{3}{5}

and divides

\frac{5}{7} \div 20

3 \frac{2}{7} - 2 \frac{1}{14} - 1 \frac{1}{14} - 1 \frac{1}{7} = ? + 2 \frac{1}{13}

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7 13 21 ? 43 57

The correct option is C 31In this series each subsequent term is obtained by adding 6,8,10,14,......respectively in the previous term. Hence the missing term is 21+10=31.

The correct option is C 31
In this series each subsequent term is obtained by adding 6,8,10,14,......
respectively in the previous term. Hence the missing term is 21+10=31.